The shape has been reflected in the line \(y = 1\). The equation of a straight line graph has the form \(y = mx + c\), where \(m\) is the gradient and \(c\) is where the line crosses the \(y\)-axis.

Find the equation of the line of symmetry and the coordinates of the turning point of the graph of \(y = x^2 - 6x + 4\). Writing \(y = x^2 - 6x + 4 \) in completed square form gives \(y = (x - 3 ...